Russian fifth-seed Andrey Rublev has saved two match points to clinch an Australian Open quarterfinal spot with a tense five-set win over Danish teenager Holger Rune.
Key points:
- Rublev won 6-3, 3-6, 6-3, 4-6, 7-6 (11/9)
- He clinched victory on his third match point via a net cord
- The Russian had trailed 0-5 during the super tie-break
Rublev staged a stunning fightback in a super tie-break to secure a a 6-3, 3-6, 6-3, 4-6, 7-6 (11/9) win with a dead net cord winner on his third match point against ninth-seed Rune.
At the end of five gripping sets, Rune raced to a 5-0 lead in the tie-break and was also up 7-3 before suffering a dramatic collapse.
Rublev snatched victory when his backhand return hit the net tape and fell over to send 19-year-old Rune crashing out of the tournament.
The result — after three hours and 37 minutes on court — sets up a blockbuster quarterfinal clash with either nine-time champion Novak Djokovic or Australian hope Alex de Minaur.
“I never was able to win matches like this,” Rublev said in his on-court interview.
“Especially in very special tournament like Australian Open, to be in quarterfinal is something that I will remember, for sure, all my life.
“I have no words, man. I’m shaking.”
Rublev was twice up a set — only to be pegged back — and was 5-2 down in the fifth set.
He saved two match points to send the fifth set to the super tie-breaker and won eight of the last 10 points to seal victory.
Young American Ben Shelton also advanced to the last eight via a five-set win, having been taken the distance by his countryman JJ Wolf.
Both players were unseeded in Melbourne, with Shelton winning 6-7 (5/7), 6-2, 6-7 (4/7), 7-6 (7/4), 6-2 after three hours and 47 minutes at the John Cain Arena.
Shelton — who ended Australian Alexei Popyrin’s tournament in the third round — is contesting just his second major.
The 20-year-old plays either 24th-seeded Spaniard Roberto Agut Bautista or fellow American Tommy Paul in the quarterfinals.
AAP/ABC